calculus help fo money

Live forum: http://forum.freeipodguide.com/viewtopic.php?t=58420

zwarrior99

01-04-2007 11:04:07

hey guys I got most of them solved thanks for the help. All i got left is these following

Here are the problems just view the image of the paper.
http//img="123.imageshack.us" alt=""/img123/9923/04012007071147pmpi8.jpg

If you can all just check them to see if there right my biggest concerns are 7,8, and 12

michae229

01-04-2007 11:35:54

I can do it if it is basic cal. i Have an A in business calculus right now what are you studying?

Brodie

01-04-2007 11:42:29

I'll help you out for free man, PM me with your questions. I mean no disrespect but buisness calc isn't exactly the same.

michae229

01-04-2007 11:53:23

[quote98dac090c3="Brodie"]I'll help you out for free man, PM me with your questions. I mean no disrespect but buisness calc isn't exactly the same.[/quote98dac090c3]

calculus is calculus

nytrate

01-04-2007 12:13:41

calculus may be calculus but what he probably means is that business calc sounds like a basic course or something like "calculus 1" as opposed to an advanced calc course.

If you have just a few Q I can help you later on via AIM for free.

mrwzk

01-04-2007 14:52:52

i will help as well if u have questions im currently in calc II

Brodie

01-04-2007 15:09:16

[quoted66a416f63="michae229"][quoted66a416f63="Brodie"]I'll help you out for free man, PM me with your questions. I mean no disrespect but buisness calc isn't exactly the same.[/quoted66a416f63]

calculus is calculus[/quoted66a416f63]

You're correct. Calculus is calculus. Unfortunately, business calculus is not. Some might even say its a joke.

michae229

01-04-2007 15:23:34

[quoted812d7113f="Brodie"][quoted812d7113f="michae229"][quoted812d7113f="Brodie"]I'll help you out for free man, PM me with your questions. I mean no disrespect but buisness calc isn't exactly the same.[/quoted812d7113f]

calculus is calculus[/quoted812d7113f]

You're correct. Calculus is calculus. Unfortunately, business calculus is not. Some might even say its a joke.[/quoted812d7113f]

yea if you take it at a BS school all it is the into part of 1,2,3

zwarrior99

02-04-2007 13:37:54

Bump I just added the questions I need these answered by tonight please help me with those.

here it is again

Differentiate
Find first and 2nd derivative
(-2)/(x^2 + 2x + 1)


Find absolute max and minimum values of the function, if they exist.

f(x) = -8x^3 +9x^2 + 6x -2



Differentiate

ln 4x


e^3x^2


e^x / ln x

manOFice

02-04-2007 13:56:57

hmm...i swear I had a calculator that did all that for me...?

Killer722

02-04-2007 14:00:44

I just took a test on all this crap.

michae229

02-04-2007 14:53:41

we just had a test over the max and min do you have to draw the derivative of the function?

zwarrior99

02-04-2007 15:59:45

guys got it scanned look at those few problems for me please!

JUNIOR6886

02-04-2007 16:44:33

[quoted89c92889a="O4F-Manofice"]hmm...i swear I had a calculator that did all that for me...?[/quoted89c92889a]

the ti-89 calculator does this iirc. But one of the points of calculus 1 is to memorize the derivative rules. Using a calculator like that totally defeats the purpose. ?

Wolfeman

02-04-2007 16:52:15

Need anymore help?

condra

02-04-2007 17:21:32

I think 7 is

f'(x) = 3liX squared li (2X)lie (to the 3xsquared)

not sure thou, has been 1 yr lol

manOFice

02-04-2007 17:37:34

heh, thats the one TI-89 thats what i used to use

Wolfeman

02-04-2007 17:46:28

[quote3f73a01ccc="condra"]I think 7 is

f'(x) = 3liX squared li (2X)lie (to the 3xsquared)

not sure thou, has been 1 yr lol[/quote3f73a01ccc]
Its actually 6xlie^(3x)

zwarrior99

02-04-2007 17:50:05

[quote441f0bf14d="Wolfeman"][quote441f0bf14d="condra"]I think 7 is

f'(x) = 3liX squared li (2X)lie (to the 3xsquared)

not sure thou, has been 1 yr lol[/quote441f0bf14d]
Its actually 6xlie^(3x)[/quote441f0bf14d]

hey lol just to be sure can you somehow put that in an image file just so I know where talking about the same answer. (maybe do it in word and put on image shack?plz) maybe do the other 8, 12 fo me lol 8)

Killer722

02-04-2007 17:55:43

8 is right. At first, I thought it was wrong, but it's right. If you need the work, I figure
ln(4x)' = 1/4x li d/dx 4x <---chain rule
1/4x li 4 <deriv of 4x
=4/4x
=1/x
...right?

zwarrior99

02-04-2007 17:57:48

[quote4e459b3c13="Killer722"]8 is right. At first, I thought it was wrong, but it's right. If you need the work, I figure
ln(4x)' = 1/4x li d/dx 4x <---chain rule
1/4x li 4 <deriv of 4x
=4/4x
=1/x
...right?[/quote4e459b3c13]

Ok thanks woot. does anyone know of a site or something since I need to turn this in and need an damn A tomorrow does any1 know of maybe a paid online tutor that can do this damn thing for make sure i got them all right?

justinag06

02-04-2007 18:05:16

ok 7) take the derivative of what is inside the e^()

Dx -> 3X^2 = 6X

and multiply that by f(x) -> 6Xlie^(3x^2)

8) it's the same as 6 if the derivative of ln(x) = dx/x then the derivative of ln(4x) = 4/x.

12) you can't cancel out of the ln(x) from the top because it isn't in the second term.

zwarrior99

02-04-2007 18:08:09

[quotee7fdd59fc1="justinag06"]ok 7) take the derivative of what is inside the e^()

Dx -> 3X^2 = 6X

and multiply that by f(x) -> 6Xlie^(3x^2)

8) it's the same as 6 if the derivative of ln(x) = dx/x then the derivative of ln(4x) = 4/x.

12) you can't cancel out of the ln(x) from the top because it isn't in the second term.[/quotee7fdd59fc1]

Guys I am sorry I am just lost please is there anyways you guys can write that in ms paint or something so I can actually see what you are saying cuz I am sort of lost translating that too paper. I am sorry for being soo annoying but this will all be repaid in good karma for helping me out lol!

Wolfeman

02-04-2007 18:08:42

i got these done and I'm working on the rest
5.) y'= 5e^x
6.) y'= 1/x
7.) f(x)= 6xe^(3x)
8.) f(x)= 1/x
9.) f(x)= e^x + 20x^4
10.) 10) f(x)= 5e^xlnx + (5e^x)/x

Brodie

03-04-2007 00:49:55

Hey man, if you still haven't completed those problems, pm me. I think you're aware, but some of those answers in that .jpgurl==http://=http:///url are wrong.

zwarrior99

03-04-2007 04:37:06

[quote33ab48cace="Brodie"]Hey man, if you still haven't completed those problems, pm me. I think you're aware, but some of those answers in that .jpgurl==http://=http:///url are wrong.[/quote33ab48cace]

pm'd you bump does anyone know of a place online with a tutor on demand that I pay. I need this stuff answered ( i got most of them but I keep getting conflicting answers from most of you). Need this in the next 5 hrs . shock

johnjimjones

03-04-2007 08:07:39

[quote0c354e992f="JUNIOR6886"][quote0c354e992f="O4F-Manofice"]hmm...i swear I had a calculator that did all that for me...?[/quote0c354e992f]

the ti-89 calculator does this iirc. But one of the points of calculus 1 is to memorize the derivative rules. Using a calculator like that totally defeats the purpose. ?[/quote0c354e992f]

Yeah, but there's no way you should need a calculator for those types of problems.

zwarrior99

03-04-2007 08:54:18

guys thanks for all the help. I ended up finding kasamba.com and I got helped there it was a bit expensive but hopefully I got it all 100% correct. You should all check out the place has a ton of tutors available online sorta like the psychics places just its tutors. WOOT

JennyWren

03-04-2007 09:28:21

So, if you need to pay someone to do your homework for you, what are you planning on doing for the exam?

Your money would be better spent on a REAL tutor who can sit down with you and help you actually LEARN the material.

zwarrior99

03-04-2007 09:38:44

[quote8a38fe18f3="JennyWren"]So, if you need to pay someone to do your homework for you, what are you planning on doing for the exam?

Your money would be better spent on a REAL tutor who can sit down with you and help you actually LEARN the material.[/quote8a38fe18f3]

thanks for your concern but it sound more like sarcasm. I did get tutored as she worked the problems out for me. I just needed to see them worked out as I know how to do it at least 60% of it I just need too see it done to learn the parts I dont know. Plus it was interactive session I can ask her questions and everything. I am not advertising for the site as I dont get a dime for you going there I am just saying incase some1 finds themselves in the same predicament as I was in.

jadem

03-04-2007 09:43:22

I know this makes me sound like a huge dork, but I miss Calculus. I wish I hadn't been forced into basic algebra freshman year at Purdue and had gone straight into calc..I would have done much better.

Seems I forgot basic algebra since I hadn't had it really, since 8th grade. /

I have also forgotten most of my advanced math that I had learned. cry

johnjimjones

03-04-2007 09:53:23

[quote31048d040c="jadem"]I know this makes me sound like a huge dork, but I miss Calculus. I wish I hadn't been forced into basic algebra freshman year at Purdue and had gone straight into calc..I would have done much better.

Seems I forgot basic algebra since I hadn't had it really, since 8th grade. /

I have also forgotten most of my advanced math that I had learned. cry[/quote31048d040c]

My friend asked me for help on some basic algebra and I almost completely forgot how to do it. I'm stuck in a differential equations mode.

mrwzk

03-04-2007 10:02:27

send me a pm next time i will glady help u calc I is cake compared to calc II

Wolfeman

03-04-2007 10:03:12

No post here so I can waste time at work...

Brodie

03-04-2007 10:21:42

paint FTW
http/" alt=""/img251.imageshack.us/img="251/7922/mathxs2.png[" alt=""/imga9b6860c06][=http//imageshack.us][img="a9b6860c06]http/" alt=""/img251.imageshack.us/img="251/7922/mathxs2.png[" alt=""/imga9b6860c06][/url]

mrwzk

03-04-2007 12:04:46

those are all the correct answers brodie has

a few rules that will make this very easy

derivative of E^x ='s (e^x) li the derivative of wats up top

derivative of ln(x) is (1/x) li the derivative of wats inside the ln

product rule is when 2 terms are multipled example is
(2x)li(E^x)

take derivative of the first term times the 2nd term + the derivative of the 2nd term times the first in this case it would be

(2)(E^x) + (e^x)(2x)

quotient rule= derivative of top times the bottom term - the derivate of the bottom times the top all over the bottom term squared

E^x/lnx= (lnx)(e^x) - (e^x)(l/x))/(lnx)^2

power rules ='s multiply the term by the power and drop it by one
5x^5 ='s 5li5x^4 which is 25x^4