calculus help fo money
zwarrior99
01-04-2007 11:04:07
hey guys I got most of them solved thanks for the help. All i got left is these following
Here are the problems just view the image of the paper.
http//img="123.imageshack.us" alt=""/img123/9923/04012007071147pmpi8.jpg
If you can all just check them to see if there right my biggest concerns are 7,8, and 12
michae229
01-04-2007 11:35:54
I can do it if it is basic cal. i Have an A in business calculus right now what are you studying?
Brodie
01-04-2007 11:42:29
I'll help you out for free man, PM me with your questions. I mean no disrespect but buisness calc isn't exactly the same.
michae229
01-04-2007 11:53:23
[quote98dac090c3="Brodie"]I'll help you out for free man, PM me with your questions. I mean no disrespect but buisness calc isn't exactly the same.[/quote98dac090c3]
calculus is calculus
nytrate
01-04-2007 12:13:41
calculus may be calculus but what he probably means is that business calc sounds like a basic course or something like "calculus 1" as opposed to an advanced calc course.
If you have just a few Q I can help you later on via AIM for free.
mrwzk
01-04-2007 14:52:52
i will help as well if u have questions im currently in calc II
Brodie
01-04-2007 15:09:16
[quoted66a416f63="michae229"][quoted66a416f63="Brodie"]I'll help you out for free man, PM me with your questions. I mean no disrespect but buisness calc isn't exactly the same.[/quoted66a416f63]
calculus is calculus[/quoted66a416f63]
You're correct. Calculus is calculus. Unfortunately, business calculus is not. Some might even say its a joke.
michae229
01-04-2007 15:23:34
[quoted812d7113f="Brodie"][quoted812d7113f="michae229"][quoted812d7113f="Brodie"]I'll help you out for free man, PM me with your questions. I mean no disrespect but buisness calc isn't exactly the same.[/quoted812d7113f]
calculus is calculus[/quoted812d7113f]
You're correct. Calculus is calculus. Unfortunately, business calculus is not. Some might even say its a joke.[/quoted812d7113f]
yea if you take it at a BS school all it is the into part of 1,2,3
zwarrior99
02-04-2007 13:37:54
Bump I just added the questions I need these answered by tonight please help me with those.
here it is again
Differentiate
Find first and 2nd derivative
(-2)/(x^2 + 2x + 1)
Find absolute max and minimum values of the function, if they exist.
f(x) = -8x^3 +9x^2 + 6x -2
Differentiate
ln 4x
e^3x^2
e^x / ln x
manOFice
02-04-2007 13:56:57
hmm...i swear I had a calculator that did all that for me...?
Killer722
02-04-2007 14:00:44
I just took a test on all this crap.
michae229
02-04-2007 14:53:41
we just had a test over the max and min do you have to draw the derivative of the function?
zwarrior99
02-04-2007 15:59:45
guys got it scanned look at those few problems for me please!
JUNIOR6886
02-04-2007 16:44:33
[quoted89c92889a="O4F-Manofice"]hmm...i swear I had a calculator that did all that for me...?[/quoted89c92889a]
the ti-89 calculator does this iirc. But one of the points of calculus 1 is to memorize the derivative rules. Using a calculator like that totally defeats the purpose. ?
Wolfeman
02-04-2007 16:52:15
Need anymore help?
condra
02-04-2007 17:21:32
I think 7 is
f'(x) = 3liX squared li (2X)lie (to the 3xsquared)
not sure thou, has been 1 yr lol
manOFice
02-04-2007 17:37:34
heh, thats the one TI-89 thats what i used to use
Wolfeman
02-04-2007 17:46:28
[quote3f73a01ccc="condra"]I think 7 is
f'(x) = 3liX squared li (2X)lie (to the 3xsquared)
not sure thou, has been 1 yr lol[/quote3f73a01ccc]
Its actually 6xlie^(3x²)
zwarrior99
02-04-2007 17:50:05
[quote441f0bf14d="Wolfeman"][quote441f0bf14d="condra"]I think 7 is
f'(x) = 3liX squared li (2X)lie (to the 3xsquared)
not sure thou, has been 1 yr lol[/quote441f0bf14d]
Its actually 6xlie^(3x²)[/quote441f0bf14d]
hey lol just to be sure can you somehow put that in an image file just so I know where talking about the same answer. (maybe do it in word and put on image shack?plz) maybe do the other 8, 12 fo me lol 8)
Killer722
02-04-2007 17:55:43
8 is right. At first, I thought it was wrong, but it's right. If you need the work, I figure
ln(4x)' = 1/4x li d/dx 4x <---chain rule
1/4x li 4 <deriv of 4x
=4/4x
=1/x
...right?
zwarrior99
02-04-2007 17:57:48
[quote4e459b3c13="Killer722"]8 is right. At first, I thought it was wrong, but it's right. If you need the work, I figure
ln(4x)' = 1/4x li d/dx 4x <---chain rule
1/4x li 4 <deriv of 4x
=4/4x
=1/x
...right?[/quote4e459b3c13]
Ok thanks woot. does anyone know of a site or something since I need to turn this in and need an damn A tomorrow does any1 know of maybe a paid online tutor that can do this damn thing for make sure i got them all right?
justinag06
02-04-2007 18:05:16
ok 7) take the derivative of what is inside the e^()
Dx -> 3X^2 = 6X
and multiply that by f(x) -> 6Xlie^(3x^2)
8) it's the same as 6 if the derivative of ln(x) = dx/x then the derivative of ln(4x) = 4/x.
12) you can't cancel out of the ln(x) from the top because it isn't in the second term.
zwarrior99
02-04-2007 18:08:09
[quotee7fdd59fc1="justinag06"]ok 7) take the derivative of what is inside the e^()
Dx -> 3X^2 = 6X
and multiply that by f(x) -> 6Xlie^(3x^2)
8) it's the same as 6 if the derivative of ln(x) = dx/x then the derivative of ln(4x) = 4/x.
12) you can't cancel out of the ln(x) from the top because it isn't in the second term.[/quotee7fdd59fc1]
Guys I am sorry I am just lost please is there anyways you guys can write that in ms paint or something so I can actually see what you are saying cuz I am sort of lost translating that too paper. I am sorry for being soo annoying but this will all be repaid in good karma for helping me out lol!
Wolfeman
02-04-2007 18:08:42
i got these done and I'm working on the rest
5.) y'= 5e^x
6.) y'= 1/x
7.) f(x)= 6xe^(3x²)
8.) f(x)= 1/x
9.) f(x)= e^x + 20x^4
10.) 10) f(x)= 5e^xlnx + (5e^x)/x
Brodie
03-04-2007 00:49:55
Hey man, if you still haven't completed those problems, pm me. I think you're aware, but some of those answers in that .jpgurl==http://=http:///url are wrong.
zwarrior99
03-04-2007 04:37:06
[quote33ab48cace="Brodie"]Hey man, if you still haven't completed those problems, pm me. I think you're aware, but some of those answers in that .jpgurl==http://=http:///url are wrong.[/quote33ab48cace]
pm'd you bump does anyone know of a place online with a tutor on demand that I pay. I need this stuff answered ( i got most of them but I keep getting conflicting answers from most of you). Need this in the next 5 hrs . shock
johnjimjones
03-04-2007 08:07:39
[quote0c354e992f="JUNIOR6886"][quote0c354e992f="O4F-Manofice"]hmm...i swear I had a calculator that did all that for me...?[/quote0c354e992f]
the ti-89 calculator does this iirc. But one of the points of calculus 1 is to memorize the derivative rules. Using a calculator like that totally defeats the purpose. ?[/quote0c354e992f]
Yeah, but there's no way you should need a calculator for those types of problems.
zwarrior99
03-04-2007 08:54:18
guys thanks for all the help. I ended up finding kasamba.com and I got helped there it was a bit expensive but hopefully I got it all 100% correct. You should all check out the place has a ton of tutors available online sorta like the psychics places just its tutors. WOOT
JennyWren
03-04-2007 09:28:21
So, if you need to pay someone to do your homework for you, what are you planning on doing for the exam?
Your money would be better spent on a REAL tutor who can sit down with you and help you actually LEARN the material.
zwarrior99
03-04-2007 09:38:44
[quote8a38fe18f3="JennyWren"]So, if you need to pay someone to do your homework for you, what are you planning on doing for the exam?
Your money would be better spent on a REAL tutor who can sit down with you and help you actually LEARN the material.[/quote8a38fe18f3]
thanks for your concern but it sound more like sarcasm. I did get tutored as she worked the problems out for me. I just needed to see them worked out as I know how to do it at least 60% of it I just need too see it done to learn the parts I dont know. Plus it was interactive session I can ask her questions and everything. I am not advertising for the site as I dont get a dime for you going there I am just saying incase some1 finds themselves in the same predicament as I was in.
jadem
03-04-2007 09:43:22
I know this makes me sound like a huge dork, but I miss Calculus. I wish I hadn't been forced into basic algebra freshman year at Purdue and had gone straight into calc..I would have done much better.
Seems I forgot basic algebra since I hadn't had it really, since 8th grade. /
I have also forgotten most of my advanced math that I had learned. cry
johnjimjones
03-04-2007 09:53:23
[quote31048d040c="jadem"]I know this makes me sound like a huge dork, but I miss Calculus. I wish I hadn't been forced into basic algebra freshman year at Purdue and had gone straight into calc..I would have done much better.
Seems I forgot basic algebra since I hadn't had it really, since 8th grade. /
I have also forgotten most of my advanced math that I had learned. cry[/quote31048d040c]
My friend asked me for help on some basic algebra and I almost completely forgot how to do it. I'm stuck in a differential equations mode.
mrwzk
03-04-2007 10:02:27
send me a pm next time i will glady help u calc I is cake compared to calc II
Wolfeman
03-04-2007 10:03:12
No post here so I can waste time at work...
Brodie
03-04-2007 10:21:42
mrwzk
03-04-2007 12:04:46
those are all the correct answers brodie has
a few rules that will make this very easy
derivative of E^x ='s (e^x) li the derivative of wats up top
derivative of ln(x) is (1/x) li the derivative of wats inside the ln
product rule is when 2 terms are multipled example is
(2x)li(E^x)
take derivative of the first term times the 2nd term + the derivative of the 2nd term times the first in this case it would be
(2)(E^x) + (e^x)(2x)
quotient rule= derivative of top times the bottom term - the derivate of the bottom times the top all over the bottom term squared
E^x/lnx= (lnx)(e^x) - (e^x)(l/x))/(lnx)^2
power rules ='s multiply the term by the power and drop it by one
5x^5 ='s 5li5x^4 which is 25x^4