Paying for an answer.

How much CO2 does the average human being respire in a year?

I need a documented source for the information. I'll pay $5 for the answer. Go google to your hearts' content.

Thanks.

164250 liters per year.
or 328500 grams per yer.

I just multiplied the values by 365.

http//en.wikipedia.org/wiki/CO2 (biology)

I don't think Wikipedia should count. I can change that information right now.

Q How much CO2 does an average person release just from breathing? And how does that compare to what my household probably uses?
A Your average human breathes out about 0.85kg of CO2 each day, or 310kg/year.

This same human does a whole bunch of other stuff - from shopping to driving to turning on lights - and for Aussies that averages about 24,600 kg CO2/year.

So basically we produce about 100 times more CO2 doing everything else we do than we produce breathing out.

(For the disturbingly curious, I present the maths

The average person exhales about 0.5 litres of air with each breath. At 15 breaths per minute, that's about 10,800 L per day.

CO2 makes up about 4% of each exhalation, so we breathe out about 432 L of CO2 daily.

Assuming my chemistry isn't completely dodgy, that works out to about 0.85 kg CO2 per day

1 mole of gas occupies 22.4L at STP
432 L C02 / 22.4 litres/mole = 19.3 moles CO2.
1 mole of CO2 weighs 44g
19.3 moles CO2 x 44 g/mole = 849g CO2
So 432L CO2/day = 0.85kg CO2/day).

http//www.abc.net.au/science/planetslayer/qa/greenhouse_qa2_29_b.htm

[quotef2ae5e6736="Daggoth"]I don't think Wikipedia should count. I can change that information right now.[/quotef2ae5e6736]

I'm actually thinking about changing it right now, just for kicks.

http//www.mrp3.com/bobf/global_warming.html[]http//www.mrp3.com/bobf/global_warming.html

hope it helps

So do I get 5 bucks or what? lol

EDIT Why didn't you just do this yourself? ?

11.04 tons per year
http//www.albertarepublicans.org/drkyoto.htm

shrug

[quoteede00fa54a]An average human being makes 18 in and exhalations per minute. As we were taught in school, oxygen from air converts in the human organism to carbon dioxide because of burning of the organic food inside. It's percentage in and exhalation is about 22%. The volume of one exhalation is 2.7 liters. So there is 0.6 liter of carbon dioxide in one exhalation, or, otherwise stated, it is 1.2 gram. It means, the average human being produces 1.2 x 18 = 21.6 gram per minute, or 0.021 x 60 x 24 = 30.24 kg per day, and 11.04 tons per year. [/quoteede00fa54a]

They are all different answers, gotta love it. But mine has math. Math rocks.

Thanks for all the fast answers. I need a documented source - such as a published refereed article, or journal citation. Wiki, or quoted professors aren't going to cut it for my needs. Also, without being a xenophobe, I'd really prefer that the answer was published in the US (it will make defense easier for my client).

+Karma for all in the interim.

Ahh now the true challenge is unveiled. I can't find shit.

[quote3b89d7ff92="johnjimjones"]Ahh now the true challenge is unveiled. I can't find shit.[/quote3b89d7ff92]

Well, and that's why I was struggling. willr91's sources suggests human respire 0.3285 metric tonnes per year (which is believable); your source suggests 11.04 tons per year (which seems outrageous).

true

I still think I had the best answer

I'm too lazy to look, but you might be able to find your answer on this site http//www.co2science.org/scripts/CO2ScienceB2C/Index.jsp

i should be able to find this for u tomorrow

[quoted72b042d1d="doylnea"]Thanks for all the fast answers. I need a documented source - such as a published refereed article, or journal citation. Wiki, or quoted professors aren't going to cut it for my needs. Also, without being a xenophobe, I'd really prefer that the answer was published in the US[bd72b042d1d] (it will make defense easier for my client)[/bd72b042d1d].

+Karma for all in the interim.[/quoted72b042d1d]

you're a lawyer?

I'd hit Google Answers or Yahoo Answers. They'll give you a great response on the cheap.

[quote907c505263="syriandoode"][quote907c505263="doylnea"]Thanks for all the fast answers. I need a documented source - such as a published refereed article, or journal citation. Wiki, or quoted professors aren't going to cut it for my needs. Also, without being a xenophobe, I'd really prefer that the answer was published in the US[b907c505263] (it will make defense easier for my client)[/b907c505263].

+Karma for all in the interim.[/quote907c505263]

you're a lawyer?[/quote907c505263]

Not sure if he is or not, but lawyers aren't the only professions that have clients. He may be a gigolo!

[quotea080080401="KeithA"]I'd hit Google Answers or Yahoo Answers. They'll give you a great response on the cheap.[/quotea080080401]

I tried looking there last night, but then got distracted. I need the answer in the short term (like today). It was my impression that GA or YA took longer than a day for an answer.

[quote22bb57a6ec="doylnea"][quote22bb57a6ec="KeithA"]I'd hit Google Answers or Yahoo Answers. They'll give you a great response on the cheap.[/quote22bb57a6ec]

I tried looking there last night, but then got distracted. I need the answer in the short term (like today). It was my impression that GA or YA took longer than a day for an answer.[/quote22bb57a6ec]

If your price is appropriate for the question, GA will get you an answer within an hour. I don't have as much experienec with YA, but I've heard it's even better.

ok
here ya go
unfortunately i dont have a scanner at home
here is your reference
National Medical Series
Physiology, 3rd Edition
Bullock, et al
Willams and Wilkins, Media, PA, USA @ 1995
page 224 -225
alveolar CO2 tension (PACO2) = k x VCO2/ VA
k=constant ~ 836 mmHg
VCO2 = CO2 production
VA= alveolar ventilation

so..
Alveolar CO2 tension is normally 40 +- 4 mmg Hg
k=863 mmhg
VA averages 4.5-5 L/min
Therefore solving for VCO2 = PACO2 x VA/k or using average numbers above
VCO2 (low) = 36 x 4.5 / 863 = .195
VCO2 (high) = 44 x 5 / 863 = .265 L CO2 /minute
LOW
.195 L/min x 60min/1 hr x 24hr/day x 365 days/year = 102.5 thousand liters/year CO2
HIGH
.265 L/min x 60min/hr x 24hrs/1 day x 365 days/year = 139 thousand liters/year CO2
as mentioned previously,
1 mole of gas occupies 22.4L at STP
139000 L C02 / 22.4 litres/mole = 6205 moles CO2.
1 mole of CO2 weighs 44g
6205 moles CO2 x 44 g/mole = 27305g CO2 for high =201.3-273kg/year using high and lows for ventilation and alveolar CO2 tension.

May I ask why in the world you'd need to prove this in a defence case?

[quote142c00212d="Darkside"]May I ask why in the world you'd need to prove this in a defence case?[/quote142c00212d]

He said client...any businessperson can have a client...not just lawyers.

[quote31557f4412="FreeOffersNow"][quote31557f4412="Darkside"]May I ask why in the world you'd need to prove this in a defence case?[/quote31557f4412]

He said client...any businessperson can have a client...not just lawyers.[/quote31557f4412]

;)

FWIW, I paid jy3 - since his answer helped me the most. For those interested, http//answers.google.com/answers/threadview?id=86080 gives a very similar answer to his (though you need to finish the math yourself to get the similar answers).

[quote76410c1ad0="doylnea"]Thanks for all the fast answers. I need a documented source - such as a published refereed article, or journal citation. Wiki, or quoted professors aren't going to cut it for my needs. Also, without being a xenophobe, I'd really prefer that the answer was published in the US (it will make defense easier for my client).

+Karma for all in the interim.[/quote76410c1ad0]

Who do you work for?

[quote9f1a646917="CollidgeGraduit"][quote9f1a646917="syriandoode"][quote9f1a646917="doylnea"]Thanks for all the fast answers. I need a documented source - such as a published refereed article, or journal citation. Wiki, or quoted professors aren't going to cut it for my needs. Also, without being a xenophobe, I'd really prefer that the answer was published in the US[b9f1a646917] (it will make defense easier for my client)[/b9f1a646917].

+Karma for all in the interim.[/quote9f1a646917]

you're a lawyer?[/quote9f1a646917]

Not sure if he is or not, but lawyers aren't the only professions that have clients. He may be a gigolo![/quote9f1a646917]

but im not so sure that gigolos defend their clients...

wait....


shock

[quotea85fc1585b="ilanbg"][quotea85fc1585b="doylnea"]Thanks for all the fast answers. I need a documented source - such as a published refereed article, or journal citation. Wiki, or quoted professors aren't going to cut it for my needs. Also, without being a xenophobe, I'd really prefer that the answer was published in the US (it will make defense easier for my client).

+Karma for all in the interim.[/quotea85fc1585b]

Who do you work for?[/quotea85fc1585b]

$10 says he doesn't tell anyone (with good reason).